Integrand size = 24, antiderivative size = 74 \[ \int \frac {\left (a^2+2 a b x^2+b^2 x^4\right )^3}{x^{10}} \, dx=-\frac {a^6}{9 x^9}-\frac {6 a^5 b}{7 x^7}-\frac {3 a^4 b^2}{x^5}-\frac {20 a^3 b^3}{3 x^3}-\frac {15 a^2 b^4}{x}+6 a b^5 x+\frac {b^6 x^3}{3} \]
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Time = 0.03 (sec) , antiderivative size = 74, normalized size of antiderivative = 1.00, number of steps used = 3, number of rules used = 2, \(\frac {\text {number of rules}}{\text {integrand size}}\) = 0.083, Rules used = {28, 276} \[ \int \frac {\left (a^2+2 a b x^2+b^2 x^4\right )^3}{x^{10}} \, dx=-\frac {a^6}{9 x^9}-\frac {6 a^5 b}{7 x^7}-\frac {3 a^4 b^2}{x^5}-\frac {20 a^3 b^3}{3 x^3}-\frac {15 a^2 b^4}{x}+6 a b^5 x+\frac {b^6 x^3}{3} \]
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Rule 28
Rule 276
Rubi steps \begin{align*} \text {integral}& = \frac {\int \frac {\left (a b+b^2 x^2\right )^6}{x^{10}} \, dx}{b^6} \\ & = \frac {\int \left (6 a b^{11}+\frac {a^6 b^6}{x^{10}}+\frac {6 a^5 b^7}{x^8}+\frac {15 a^4 b^8}{x^6}+\frac {20 a^3 b^9}{x^4}+\frac {15 a^2 b^{10}}{x^2}+b^{12} x^2\right ) \, dx}{b^6} \\ & = -\frac {a^6}{9 x^9}-\frac {6 a^5 b}{7 x^7}-\frac {3 a^4 b^2}{x^5}-\frac {20 a^3 b^3}{3 x^3}-\frac {15 a^2 b^4}{x}+6 a b^5 x+\frac {b^6 x^3}{3} \\ \end{align*}
Time = 0.01 (sec) , antiderivative size = 74, normalized size of antiderivative = 1.00 \[ \int \frac {\left (a^2+2 a b x^2+b^2 x^4\right )^3}{x^{10}} \, dx=-\frac {a^6}{9 x^9}-\frac {6 a^5 b}{7 x^7}-\frac {3 a^4 b^2}{x^5}-\frac {20 a^3 b^3}{3 x^3}-\frac {15 a^2 b^4}{x}+6 a b^5 x+\frac {b^6 x^3}{3} \]
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Time = 0.04 (sec) , antiderivative size = 67, normalized size of antiderivative = 0.91
method | result | size |
default | \(-\frac {a^{6}}{9 x^{9}}-\frac {6 a^{5} b}{7 x^{7}}-\frac {3 a^{4} b^{2}}{x^{5}}-\frac {20 a^{3} b^{3}}{3 x^{3}}-\frac {15 a^{2} b^{4}}{x}+6 a \,b^{5} x +\frac {b^{6} x^{3}}{3}\) | \(67\) |
risch | \(\frac {b^{6} x^{3}}{3}+6 a \,b^{5} x +\frac {-15 a^{2} b^{4} x^{8}-\frac {20}{3} a^{3} b^{3} x^{6}-3 a^{4} b^{2} x^{4}-\frac {6}{7} a^{5} b \,x^{2}-\frac {1}{9} a^{6}}{x^{9}}\) | \(69\) |
norman | \(\frac {\frac {1}{3} b^{6} x^{12}+6 a \,b^{5} x^{10}-15 a^{2} b^{4} x^{8}-\frac {20}{3} a^{3} b^{3} x^{6}-3 a^{4} b^{2} x^{4}-\frac {6}{7} a^{5} b \,x^{2}-\frac {1}{9} a^{6}}{x^{9}}\) | \(70\) |
gosper | \(-\frac {-21 b^{6} x^{12}-378 a \,b^{5} x^{10}+945 a^{2} b^{4} x^{8}+420 a^{3} b^{3} x^{6}+189 a^{4} b^{2} x^{4}+54 a^{5} b \,x^{2}+7 a^{6}}{63 x^{9}}\) | \(71\) |
parallelrisch | \(\frac {21 b^{6} x^{12}+378 a \,b^{5} x^{10}-945 a^{2} b^{4} x^{8}-420 a^{3} b^{3} x^{6}-189 a^{4} b^{2} x^{4}-54 a^{5} b \,x^{2}-7 a^{6}}{63 x^{9}}\) | \(71\) |
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Time = 0.24 (sec) , antiderivative size = 70, normalized size of antiderivative = 0.95 \[ \int \frac {\left (a^2+2 a b x^2+b^2 x^4\right )^3}{x^{10}} \, dx=\frac {21 \, b^{6} x^{12} + 378 \, a b^{5} x^{10} - 945 \, a^{2} b^{4} x^{8} - 420 \, a^{3} b^{3} x^{6} - 189 \, a^{4} b^{2} x^{4} - 54 \, a^{5} b x^{2} - 7 \, a^{6}}{63 \, x^{9}} \]
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Time = 0.19 (sec) , antiderivative size = 73, normalized size of antiderivative = 0.99 \[ \int \frac {\left (a^2+2 a b x^2+b^2 x^4\right )^3}{x^{10}} \, dx=6 a b^{5} x + \frac {b^{6} x^{3}}{3} + \frac {- 7 a^{6} - 54 a^{5} b x^{2} - 189 a^{4} b^{2} x^{4} - 420 a^{3} b^{3} x^{6} - 945 a^{2} b^{4} x^{8}}{63 x^{9}} \]
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Time = 0.19 (sec) , antiderivative size = 69, normalized size of antiderivative = 0.93 \[ \int \frac {\left (a^2+2 a b x^2+b^2 x^4\right )^3}{x^{10}} \, dx=\frac {1}{3} \, b^{6} x^{3} + 6 \, a b^{5} x - \frac {945 \, a^{2} b^{4} x^{8} + 420 \, a^{3} b^{3} x^{6} + 189 \, a^{4} b^{2} x^{4} + 54 \, a^{5} b x^{2} + 7 \, a^{6}}{63 \, x^{9}} \]
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Time = 0.27 (sec) , antiderivative size = 69, normalized size of antiderivative = 0.93 \[ \int \frac {\left (a^2+2 a b x^2+b^2 x^4\right )^3}{x^{10}} \, dx=\frac {1}{3} \, b^{6} x^{3} + 6 \, a b^{5} x - \frac {945 \, a^{2} b^{4} x^{8} + 420 \, a^{3} b^{3} x^{6} + 189 \, a^{4} b^{2} x^{4} + 54 \, a^{5} b x^{2} + 7 \, a^{6}}{63 \, x^{9}} \]
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Time = 0.05 (sec) , antiderivative size = 70, normalized size of antiderivative = 0.95 \[ \int \frac {\left (a^2+2 a b x^2+b^2 x^4\right )^3}{x^{10}} \, dx=-\frac {\frac {a^6}{9}+\frac {6\,a^5\,b\,x^2}{7}+3\,a^4\,b^2\,x^4+\frac {20\,a^3\,b^3\,x^6}{3}+15\,a^2\,b^4\,x^8-6\,a\,b^5\,x^{10}-\frac {b^6\,x^{12}}{3}}{x^9} \]
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